I know nobody ever reads this but hey! I'm Bree.
Welcome to my amazingly awesome new profile. I know it's basically the same as all my other profiles but this one's inspired by like... night-vision goggles, guns, you know, spy stuff.
When I was in primary school, my friends and I played spies ALL the time! My spy name was Serenity. I don't know how I chose it, but I think it's a pretty name =)
I actually like learning. It doesn't necessarily mean that I'm a good student or anything. I just like... knowing stuff?
I really enjoy that feeling of helping people but I don't usually do charities and stuff. I usually just try help people with their questions, help them carry stuff, things like that =)
Name: Bree. That's why my username is Breeze. Get it? =) I was going to write "Bree's Breeze" as my header but I decided I'd make it more spy-ish
Age: 16 and growing older
Country: Australia
Books: Uglies, The Midnighters, Vampire Academy (and Bloodlines), Harry Potter, Hunger Games, Airhead, Mediator... Can't think of anymore atm...
Likes: Chocolate, breakfast juice (Berri), friends, photography, Ben 10
Dislikes: Crying (I cry too easily), people who over-swear, homework, tutoring, horror
Overview: I'm totally modest, super friendly and I try to NEVER get on people's bad sides. Accidents happen, though.
Anything else I need to put here?
Series
& Sequences
Sorry it's so long! And I
couldn't be bothered to make the fractions...
Sequence: A
bunch of ordered numbers.
Series: A
bunch of ordered numbers added
together.
Arithmetic
series: Numbers differ by a certain number
Eg, 2 + 5 + 8 + 11...
Geometric
series: Numbers which differ in a ratio. The
third number over the second number is EQUAL to the second
over the first.
Eg, 3 + 9 + 27 +
81...
Arithmetic
series formulae:
Finding a
term:
Tn = a +
(n-1)d
Tn = nth term
a = first term
n = number of terms
d = difference between each term (sometimes
negative)
Sn = (n/2)(a + l
)
Sn = Sum of n terms
l = last term
Sn = (n/2)[2a +
(n-1)d]
Can be derived from the 2nd
equation
Geometric
series formulae:
Tn = ar^(n-1)
r = ratio of terms. To find
this, divide the second term by the first
term.
Sn =
[a(r^n-1)]/(r-1)
If lrl >
1
Sn =
[a(1-r^n)]/(1-r)
If lrl <
1
S∞ = a/(1-r)
S∞ = Sum of an infinite
number of terms.
Only happens when lrl < 1
(ie, a converging series such as 1 + 1/2 + 1/4 +
1/8 + 1/16 +...+ 1/big number (which approximately = 0) = 2
)